(2x+3)(2x^2-17x+35)=0

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Solution for (2x+3)(2x^2-17x+35)=0 equation: 


Simplifying
(2x + 3)(2x2 + -17x + 35) = 0

Reorder the terms:
(3 + 2x)(2x2 + -17x + 35) = 0

Reorder the terms:
(3 + 2x)(35 + -17x + 2x2) = 0

Multiply (3 + 2x) * (35 + -17x + 2x2)
(3(35 + -17x + 2x2) + 2x * (35 + -17x + 2x2)) = 0
((35 * 3 + -17x * 3 + 2x2 * 3) + 2x * (35 + -17x + 2x2)) = 0
((105 + -51x + 6x2) + 2x * (35 + -17x + 2x2)) = 0
(105 + -51x + 6x2 + (35 * 2x + -17x * 2x + 2x2 * 2x)) = 0
(105 + -51x + 6x2 + (70x + -34x2 + 4x3)) = 0

Reorder the terms:
(105 + -51x + 70x + 6x2 + -34x2 + 4x3) = 0

Combine like terms: -51x + 70x = 19x
(105 + 19x + 6x2 + -34x2 + 4x3) = 0

Combine like terms: 6x2 + -34x2 = -28x2
(105 + 19x + -28x2 + 4x3) = 0

Solving
105 + 19x + -28x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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